If two given straight lines cut one another, they make the vertical angles equal to one another.
For let the straight lines AB, CD cut one another at the point E;
I say that the angle AEC is equal to the angle DEB,
and the angle CEB to the angle AED.
For, since the straight line AE stands on the straight line CD, making
the angles CEA, AED, the angles CEA, AED are equal to two right angles.
Again, since the straight line DE stands on the straight line AB, making
the angles AED, DEB, the angles AED, DEB are equal to two right angles.
But the angles CEA, AED were also proved equal to two right angles;
therefore the angles CEA, AED are equal to the angles AED, DEB.
Let the angle AED be subtracted from each;
therefore the remaining angle CEA is equal to the remaining angle BED
Similarly it can be proved that the angles CEB, DEA are also equal.
Therefore etc.
Q.E.D