Proposition 36.
Parallelograms which are on equal bases and in the same parallels are equal
to one another.
Let ABCD, EFGH be parallelograms which are on equal bases BC, FG and in the
same parallels AH, BG;
I say that the parallelogram ABCD is equal to EFGH.
For, let BE, CH be joined.
while FG is equal to EH, BC is also equal to EH
But they are also parallel.
And EB, HC join them;
but straight lines joining equal and parallel straight lines (at the
extremeties which are) in the same directions (respectively) are equal and
parallel.
Therefore EBCH is a parallelogram.
And it is equal to ABCD;
for it has the same base BC with it, and is in the same paralllels BC, AH
with it.
For the same reason also EFGH is equal to the same EBCH
so that the parallelogram ABCD is also equal to EFGH.
Therefore etc.
Q.E.D
Ralph H. Abraham, 28 April, 1996.