Proposition 10.

Of magnitudes which have a ratio to the same, that which has a greater ratio is greater; and that to which the same has a greater ratio is less.


For let A have to C a greater ratio than B has to C;

I say that A is greater than B.

For, if not, A is either equal to B or less.

Now A is not equal to B;

for in that case each of the magnitudes A, B would have had the same ratio to C;

but they have not; therefore A is not equal to B.

Nor again is A less than B;

for in that case A would have had to C a less ratio than B has to C;

but it has not; therefore A is not less than B.

But it was proved not to be equal either; therefore A is greater than B.

Again, let C have to B a greater ratio than C has to A;

I say that B is less than A.

For, if not, it is either equal or greater.

Now B is not equal to A;

for in that case C would have had the same ratio to each of the magnitudes A, B; but it has not;

therefore A is not equal to B.

Nor again is B greater than A;

for in that case C would have had to B a less ratio than it has to A; but it has not;

therefore B is not greater than A.

But it was proved that it is not equal either; therefore B is less than A.


Therefore etc.

Q.E.D


Ralph H. Abraham, 28 April, 1996.