Parts have the same ratio as the same multiples of them taken in corresponding order.
For let AB be the same multiple of C that DE is of F;
I say that, as C is to F, so is AB to DE.
For, since AB is the same multiple of C that DE is of F, as many magnitudes as
there are in AB equal to C, so many are there also in DE equal to F. Let AB be
divided into the magnitudes AG, GH, HB equal to C, and DE into the magnitudes
DK, KL, LE equal to F; then the multiple of the magnitudes AG, GH, HB will be
equal to the multitude of the magnitudes DK, KL, LE.
And, since AG, GH, HB are equal to one another, and DK, KL, LE are also equal
to one another, therefore, as AG is to DK, so is GH to KL, and HB to LE.
Therefore, as one of the antecedents is to one of the consequents, so will all
the antecedents be to all the consequents;
therefore, as AG is to DK, so is AB to DE.But AG is equal to C and DK to F;
therefore, as C is to F, so is AB to DE.
Therefore etc.
Q.E.D