If there be three magnitudes, and others equal to them in multitude, which taken two and two together are in the same ratio, and the proportion of them be perturbed, then, if ex aequali the first magnitude is greater than the third, the fourth will also be greater than the sixth; if equal, equal; and if less, less.
Let there be three magnitudes A, B, C, and others D, E, F equal to them in
multitude,
which taken two and two are in the same ratio, and let the proportion of them
be perturbed, so that, as A is to B, so is E to F,
and, as B is to C, so is D to E,
and let A be greater than C ex aequali;
I say that D will also be greater than F; if A is equal to C, equal; and if
less, less.
For, since A is greater than C, and B is some other magnitude, therefore A has
to B a greater ratio than C has to B.
But, as A is to B, so is E to F, and, as C is to B, inversely, so is E to D.
Therefore also E has to F a greater ratio than E has to D.
But that to which the same has a greater ratio is less; therefore F is less
than D; therefore D is greater than F.
Similarly we can prove that, if A be equal to C, D will also be equal to F;
and if less, less.
Therefore etc.
Q.E.D